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Let h d ( n )be the unit sample response of an ideal filter that is to be approximated by a causal filter that has a unit sample response, h ( n ) ,and a rational system function,

Fig. 6-23

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Because H ( z ) has p q 1 free parameters, it is generally possible to find values for the coefficients a ( k ) and h(k) so that h ( n ) = h d ( n )for n = 0, 1 , . . . , p q . The procedure that is used to find these coefficients is to write H ( z ) = B ( z ) / A ( z )as follows,

Fig. 6-24

lim [ f (x) g(x)] = lim f (x) lim g(x)

(note that b(n) is a finite-length sequence that is equal to zero for n .c0 and n z q). Setting h ( n ) = hd(n)for n = 0 1, . . . , p q results in a set of p q + 1 linear equations in p q + 1 unknowns, .

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6.5 Triangles and quadrilaterals having tangent sides Points P, Q, and R in Fig. 6-25 are points of tangency.

hd(n)

Fig. 6-25

-k ) =

lim x 2 = lim x lim x = a a = a2 x a x a x a More generally, for any positive integer n, lim x n = an . x a

that may be solved using a two-step approach. In the first step, the coefficients a ( k ) are found using the last p equations in Eq. (9.14),which may be written in matrix form as

OP, what kind of triangle is OPA PQ, what kind of triangle is APQ OP, what kind of quadrilateral is OPAQ

Assuming that these equations are linearly independent, the coefficients may be uniquely determined. In the second step, the coefficients b ( k ) are found from the first 9 1 equations in Eq. (9.14) as follows:

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(a) AP is tangent to the circle at P; then by Principle 1, j OPA is a right angle. Also, AP is an isosceles right triangle. (b) AP and AQ are tangents from a point to the circle; hence by Principle 4, AP ^ APQ is an equilateral triangle. (c) By Principle 4, AP Then AP AQ OP AQ. Also, OP and OQ are > radii. And AP OP. Hence, ^ OAP PQ. Then

Although PadC's method produces an exact match of h ( n ) to h d ( n )for n = 0. 1. . . . , p 9, because h ( n ) is unconstrained for n > p q , the PadC method does not generally produce a good approximation to h d ( n )for n > p+q.

(d) By Principle 1, AP ' PR and BR ' PR. Then AP i BR, since both are ' to PR. By Principle 1, AB ' OQ; also, PR ' OQ (Given). Then AB i PR, since both are ' to OQ. Hence, PABR is a parallelogram with a right angle, or a rectangle.

With a least-squares approach to filter design, the problem is to find the coefficients a ( k ) and b ( k )that minimize the least-squares error

If f and g are functions,

2:3. 140 .

where U is some preselected upper limit. Because E is a nonlinear function of the coefficients a ( k ) and b(k), solving this minimization problem is, in general, difficult. With Prony's method, however, an approximate least-squares solution may be found using a two-step procedure as follows. Ideally, because [see Eq. (9.14)]

(c) In Fig. 6-26(c), DP and CQ are tangents. Find mj 2 and mj 3 if j OPD is trisected and PQ is a diameter.

where Once the coefficients a ( k ) have been determined, the coefficients h ( k ) are found using the PadC approach of' forcing h ( n ) = h d ( n )for n = 0, 1. . . . , 9 :

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